QUOTE(belicked6924 @ Mar 8 2006, 11:54 PM)
C = 5/9 * (F - 32)
F = 9/5 * (C + 32)
Let me see, Is this a pointless thread? No! It's Natalie's abd she's definitely hot so she'll let me ramble.
I had a physics teacher in high school that said, "Stop trying to remember two formulas. Simplify the algebraic equation by multipling both sides of the equation by 9.
9* C = 9* 5/9(F - 32)
9C = 5(F - 32)
9C = 5F - 160 <<<This was the formula we were suppose to use on tests, home work, etc.The test to know whether you have remembered the correct formula is -40C = -40F. It is know as the cross over point where the graphs of the two temperatures intersect.
So let us put this check into Belicks' second equation. I think we will find that the parenthesis don't belong. Belicks' second equation was: F = 9/5 * (C + 32)
First we'll simplify it.
5*F = 5* {9/5 * (C + 32)}
5F = 9*(C+32)
5F = 9C + 288
Now well insert the crossover temperatrue.
5*(-40) = 9(-40) + 288
-200 does not equal -72
If we rewrite Belicks' second equation as F = 9/5 * C + 32.
F = 9/5C + 32
multiply both sides of the equation by 5 to simplify & getrid of the fraction .
5F = 9C + 160
Now insert the crossover temperature of -40
5(-40) = 9(-40) + 160
-200 = -360 + 160
-200 = -200
So the two equations are
C = 5/9 * (F - 32)
F = 9/5 * C + 32
Most chemistry students use calculators so that gets simplified into the decimal fraction of 1.8 instead of 9/5.
The final equation becomes
F = 1.8C + 32Learn the red equation or learn the purple equation or better yet don't bother unless you are really doing research. Then you would probably do it in the metric system anyhow.
The above post (meaning mine not Belicks') is true but alot of pedantic BS! Lets see some lovely breasts. Please Natalie.